検索キーワード「axis of symmetry」に一致する投稿を日付順に表示しています。 関連性の高い順 すべての投稿を表示
検索キーワード「axis of symmetry」に一致する投稿を日付順に表示しています。 関連性の高い順 すべての投稿を表示

画像 y=x^2+2x-8 in vertex form 148775-Y=-3x^2-x-8 in vertex form

10 2 Quadratics In Vertex Form Youtube

10 2 Quadratics In Vertex Form Youtube

 The standard form of the parabola with vertex (h, k) and axis of symmetry x = h is y = a(x h)2 k The vertex form of the equation of parabola is y = 2 (x 3/4)2 9/8 and Vertex (h, k ) = (3/4, 9/8) answered by steve Scholar edited by steve Please log in or register to add a commentDivide 22\sqrt {y} by 2 The equation is now solved Swap sides so that all variable terms are on the left hand side Factor x^ {2}2x1 In general, when x^ {2}bxc is a perfect square, it can always be factored as \left (x\frac {b} {2}\right)^ {2} Take the square root of

Y=-3x^2-x-8 in vertex form

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